A. write an equation for determining the number of moles of naoh that are added to the flask based on [naoh] and volume of naoh titrant (ml naoh): b. write a similar expression for the number of moles of h2so4 in the flask based on [h2so4] and the volume of h2so4 (ml). substitute your expressions from a and b into this equation and solve for [h2so4]

From the equation for molarity (number of moles of a substance dissolved in one liter of solution), we can get an equation for determining the number of moles:

c=n/V   ⇒   n=c×V

Now, we can write required equations:

A   n(NaOH)=c(NaOH)×V(NaOH)

B    n(H₂SO₄)=c(H₂SO₄)×V(H₂SO₄) 

From the reaction, we can conclude that NaOH and H₂SO₄ have following stoichiometric ratio:

2NaOH + H₂SO₄ ⇒ Na₂SO₄ + 2H₂0

n(NaOH) : n(H₂SO₄) = 2 : 1

So, we can write:

n(NaOH) = 2 × n(H₂SO₄)

And if we connect the above equations, we get the equation for solving c(H2SO4):

c(NaOH)×V(NaOH) = 2×c(H₂SO₄)×V(H₂SO₄)

c(H₂SO₄) = (c(NaOH)×V(NaOH)) / (2×V(H₂SO₄))

Ok where is the image ?