What is the molarity of a naoh solution if 15.0 ml of the solution is neutralized by 38.5 ml 0.150 m h3po4 solution?

The solution for this problem is:
Look for the moles of NaOH which is 0.0385 L x 0.150 M = 0.00578 
H3PO4 + 3 NaOH = Na3PO4 + 3 H2O 
moles H3PO4 = 0.00578 / 3 = 0.00193 
M of H3PO4 = 0.00193 mol / 0.0150 L= 0.128 is the molality we are looking for in this problem.

Letter a hope it

You need to divided twenty four by a dozen them by the temperature it is getting cook by