Draw the molecule draw the acetal produced when ethanol adds to propanone. n the canvas by choosing buttons from the tools (for bonds), atoms, and advanced template toolbars. the single bond is active by default.

The structure of acetal produced by addition of alcohols to propanone is shown in the attached image.

Further Explanation:

Alcohols undergo addition with carbonyl groups and form hemiacetals and acetals. Reversible addition of alcohols to aldehydes and ketones yields hemiacetals, which on further addition of alcohols forms acetals. Acid catalyst should be present for this reaction to take place. This is necessary step to make alcohol good nucleophile. Water produced during this reaction should be removed with the help of molecular sieves.

Acetals are the derivatives of ketones or aldehydes that are produced by the reaction of two moles of alcohol with water being removed from the reaction. In formation of acetals, hemiacetals are formed as intermediates. Acetals are more stable as compared to hemiacetals.

Ethanol is an alcohol with two carbon atoms while propanone is ketone having three carbon atoms. So ethanol reacts with propanone in presence of acid catalyst to form acetal. (For reaction, refer to the attached image). Therefore structure of acetal formed by such a reaction is shown in the attached image.

Learn more:

1. What is the empirical formula of the compound?

2. Write the name of the hydrocarbon:

Answer Details:

Grade: Senior School

Subject: Chemistry

Chapter: Alcohols

Keywords: alcohol, acetal, hemiacetal, ketone, aldehyde, intermediates, derivatives, water, nucleophile, molecular sieves, carbonyl groups, reversible addition, ethanol, propanone, more stable, two carbon atoms, three carbon atoms.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2