A0.477 mol sample of o2 gas has a volume of 12.1 l at a certain temperature and pressure. if all this o2 were converted to ozone (o3 ) at the same temperature and pressure, what is the ozone volume (in liters)? 3o2 (g) → 2o3 (g)

If we are assuming ideal behavior, then the Ideal Gas Equation, , is very helpful. The number of moles changes here by a factor of , so you have . 

So,  and . Looking at the given information, P and T are constant (as is R, always). So, we can write . Solving for , we get . Then we plug in 12.1 L for ,  for  and  for . Thus .

Ithink the answer is 56.

The answer to your question really depends on three things: how much water you have, how cold it is to start out, and how cold the things around it are. water actually freezes when it gets to 32 degrees fahrenheit (0 degrees celsius), but the time it takes to get there may be different.  let's start with the first. if you take two glasses, and fill one with a tiny bit of water, and the other about halfway, then put them both in the freezer, the one with less water will freeze first (you can try this at home, but i recommend using plastic cups and not glass ones).  now let's move on to the second part. let's say you have two glasses, and you fill one with really cold water that has been in the refrigerator, and the other with really hot water from the sink. if you put both of them in the freezer, the one that started out colder will freeze first.  for the third part, let's imagine that you have two glasses with the same amount of water in them, and the water is at the same temperature. imagine putting one outside on a really really cold day in georgia, and having a friend in alaska put one outside on the same day. since it would be so much colder in alaska, the glass of water there would freeze before yours.  so, if you took a tiny bit of really cold water in a glass, and put it outside on a cold day in alaska, it would freeze a lot faster than a big glass of hot water outside on a cold day in georgia.