How many moles of co2 are produced when 5.30 mol of ethane are burned in an excess of oxygen?

When 2C2H6 (g) + 7 O2 (g) ⇒ 4CO2 (g) + 6H2O (L) is the balanced equation for this reaction:
So from the equation, 2 mol of C2H6 gives → 4 mol of CO2
So the molar ratio between C2H6 & CO2 is 

2 mol C2H6:4 mol CO2 we can make it:
1 mol C2H6: 2 mol Co2 
So when we have 5.3 mol of C2H6 how many moles of CO2 then
the moles of CO2 = 5.3 * 2 mol (CO2) / 1 mol (C2H6)
                               = 10.6 mol

Ithink it’s carbon dioxide