If a saturated solution of nh4no3 at 75 °c is cooled to 15 °c, how many grams of solute will separate if the quantity of the solvent is 127 g? answers

Solubility of ammonium nitrate in water at 15°C is 173 g.
Solubility of ammonium nitrate in water at 75°C is 499 g.
m(water) = 127 g.
15°C:
173 g : 100 g = m(NH₄NO₃) : 127 g.
m(NH₄NO₃) = 219,71 g.
75°C:
499 g : 100 g = m(NH₄NO₃) : 127 g.
m(NH₄NO₃) = 633,73 g.
m(NH₄NO₃) = 633,73 g - 219,71.
m(NH₄NO₃) = 414,02 g.

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