Asolution contains 48.6 g glucose (c6h12o6) dissolved in 0.800 l of water. what is the molality of the solution? (assume a density of 1.00 g/ml for water.)

Explanation:

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In this case, since the molality is defined in terms of the moles of solute divided by the kilograms of solvent as shown below:

One firstly computed the moles of glucose which acts as the solute as follows:

Now, as the density of water is 1.00 g/mL, we conclude we have 0.8 kg of water, therefore, the resulting molality in molar units (m) turns out:

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