How many grams of titanium could be obtained from a 27.00 mole sample of ti6al4v?

7754 g

Explanation:

According to the chemical formula, in 1 mole of Ti₆Al₄V, there are 6 moles of titanium. The moles of titanium in 27.00 moles of Ti₆Al₄V are:

27.00 mol Ti₆Al₄V × (6 mol Ti/1 mol Ti₆Al₄V) = 162.0 mol Ti

The molar mass of titanium is 47.867 g/mol. The mass corresponding to 162.0 moles is:

162.0 mol × (47.867 g/mol) = 7754 g

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