An aqueous solution of licl is 34.0 % licl. what mass of water is present in 250.0 g of the solution? (density of water is 1.00 g/ml) (solution contains only licl and water.)

Mass of water present in 250 g of solution is 165 g

Explanation:

A solution contains solute and solvent. A solute is defined as the substance which is present in smaller proportion and solvent is defined as the substance which is present in larger proportion.

We are given:

34 % (m/m) of LiCl

This means that 34 g of LiCl is present in 100 g of solution.

Mass of water in solution = 100 - 34 = 66 g

We need to find the mass of water present in 250 g of solution. By applying unitary method, we get:

In 100 g of solution, mass of water present in 66 g

So, in 250 g of solution, mass of water present will be =

Hence, mass of water present in 250 g of solution is 165 g

i dont know

explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :