Chemistry, 04.08.2019 02:00 natalieoppelt
Ethyl chloride vapor decomposes by the first-order reaction c2h5cl → c2h4 hcl the activation energy is 249 kj/mol and the frequency factor is 1.6 × 1014 s−1. find the temperature at which the rate of the reaction would be twice as fast as when the reaction runs at 730.6 k. enter your answer numerically and in terms of kelvin.
Answers: 1
![\log \frac{K_2}{K_1}=\frac{E_a}{2.303R}\times [\frac{T_2-T_1}{T_1T_2}]](/tpl/images/0167/7789/e0c66.png)
= rate of reaction at 
= rate of reaction at 
= activation energy
![\log \frac{2K_1}{K_1}=\frac{249000 kJ/mol}{2.303\times 8.314 J/mol K}\times [\frac{T_2-730.6 K}{730.6 K\times T_2}]](/tpl/images/0167/7789/638fd.png)
![0.3010=\frac{249000 J/mol}{2.303\times 8.314 J/mol K}\times [\frac{T_2-730.6 K}{730.6 K\times T_2}]](/tpl/images/0167/7789/3fa9a.png)
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Ethyl chloride vapor decomposes by the first-order reaction c2h5cl → c2h4 hcl the activation energy...
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