How many grams of water are in 4.589 x 10^23 molecules of water (h2o)? okay i'm trying this by every mole to gram method for an hour and still can't solve pl me

Answer is: 13.7 grams of water.

N(H₂O) = 4.589·10²³; number of water molecules.

n(H₂O) = N(H₂O) ÷ Na(Avogadro constant).

n(H₂O) = 4.589·10²³ ÷ 6.022·10²³ 1/mol.

n(H₂O) = 0.76 mol; amount of substance.

M(H₂O) = 2 · Ar(H) + Ar(O) · g/mol.

M(H₂O) = 2 · 1 + 16 · g/mol.

M(H₂O) = 18 g/mol; molar mass of water.

m(H₂O) = n(H₂O) · M(H₂O).

m(H₂O) = 0.76 mol · 18 g/mol.

m(H₂O) = 13.7 g.

the answer for sodium is 0.186

the answer for rubidium is 0.251