What mass of propane (c3h8) is needed to produce 346 g carbon dioxide in the following reaction? a. 346 g c3h8 b. 1.86 g c3h8 c. 5075 g c3h8 d. 115 g c3h8

Answer : The correct option is, (D) 115 grams

Explanation :

Mass of = 346 g

Molar mass of = 44 g/mole

Molar mass of = 44 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of .

The balanced chemical reaction is,

From the balanced reaction we conclude that,

As, 3 mole of obtained from 1 mole of

So, 7.86 moles of react to give moles of

Now we have to calculate the mass of .

Therefore, the mass of propane needed are, 115 grams

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43.452

step-by-step explanation:

284 times .153 = 43.452