Aresearcher is designing a laboratory experiment to determine whether the inorganic substance a affects the rate of a reaction between two colored liquids, x and y. when the reaction is complete, the liquid is clear. the reaction between x and y is similar to one used by manufacturers to produce certain chemicals in factories. which method would best answer his question about reaction rate and what will he find out about substance a?

Answer : First, he should measure how long it takes for the liquid to become clear if X and Y are mixed together. Then, he should measure how long it takes if he also adds substance A to X and Y. He will find out if substance A is a catalyst

Explanation : Measuring the time taken for the liquid to become clear when X and Y were mixed together will give an assumption about the reaction time and the rate of reaction.

Then same measurement should be done when the substance A is added to the liquid of X and Y mixture. If there is a fast reaction that occurs when A is added to the reaction mixture then it can be concluded that A acts as an catalyst for mixing X with Y. Also, by comparing the reaction rates of both the reaction it can be easily concluded that A was a catalyst or not.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2