What is the maximum number of moles of alcl3 that can be produced from 5.0 mol al and 6.0 mol cl2? 2al + 3cl2 -> 2alcl3

Maximum number of moles of AlCl3 produced is 5 moles

Explanation:

First thing's first, let's bring out the balanced chemical equation.

2Al + 3Cl2 -> 2AlCl3

Before proceeding to calculating the maximum number of moles of AlCl3 that can be formed, we have to identify the limiting reagent.

Every 2 mole of AlCl3 requires 2 moles of Al and  3 moles of Cl2.

If all of the 5 moles of Al were to be used up, there would need to be 5 × (2 / 3) or 3.333 moles of Cl2. 6 moles of Cl2 is available, this means Al is our limiting reagent.

5 mol of Al * (2 mol of Cl2 / 3 mol of Al)  = 3.33 mol of Cl2

From the equation, 2 mol of Al produces 2 mol of AlCl3. This means 5 mol of Al would produce x?

2 = 2

5 = x

x = (5 * 2 ) / 2

x = 10 /2 = 5

Maximum number of moles of AlCl3 produced is 5 moles

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.