An apprentice jeweler determines the density of a sample of pure gold to be 20.3 g/cm3. the accepted value is 19.3 g/cm3. what is the percent error of the jeweler's density measurement?

We are tasked to find the percent error of the jeweler's density measurement through the formula:

%Error= Absolute Value(Experimental Value - Theoretical value) x 100%/ Theoretical Value

We are given by the problem,
Experimental Value=20.3 g/cm3
Theoretical Value= 19.3 g/cm3
By Substituting the details,
%Error= Absolute Value(20.3 g/cm3 - 19.3 g/cm3) x 100% / 19.3 g/cm3
%Error=Absolute Value (1)/19.3
%Error= 100/19.3
%Error= 5.18%

Therefore, 5.18% is the percent error committed by the jeweler

accepted value - experimental value / accepted value * 100 = percent error (19.3 g/cm3 - 20.3 g/cm3) / (19.3 g/cm3) * 100% = 5.18 g/cm3

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.