How many moles of ions are in 285 ml of 0.0150 m mgcl2?

Answer : The number of moles of and ions are 0.00428 and 0.00856 moles respectively.

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

In this question, the solute is .

Given :

Volume of solution = 285 mL = 0.285 L    (1 L = 1000 mL)

Molarity = 0.0150 M

Now put all the given values in this formula, we get:

Thus, the number of moles of are 0.00428 moles.

By the stoichiometry we can say that, 1 moles of dissociates to give 1 mole of ion and 2 moles of ions.

So,

Number of moles of ion = 0.00428 mole

Number of moles of ion = 2 × 0.00428 = 0.00856 mole

Therefore, the number of moles of and ions are 0.00428 and 0.00856 moles respectively.

i have no clue hope you find the answer

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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