Upon balancing the equation below, how many moles of sulfuric acid are needed to react completely with 6.4 moles of lithium hydroxide? lioh + h2so4 yields li2so4 + h2o (2 points) a.) 12.8 mol h2so4 b.) 6.4 mol h2so4 c.) 3.2 mol h2so4 d.) 2.1 mol h2so4

  the moles   of   sulfuric acid   that are needed to react   completely with 6.4   moles   of lithium hydroxide   is 12.8   moles ( answer a)

calculation

step 1 : write a balanced   chemical equation

2lioh   + h₂so₄   →   li₂so₄   +2h₂o

step 2 : use the mole ratio   to determine   the   moles h₂so₄

from   equation above   lioh: h₂so₄   is 2: 1 therefore   the moles of h₂so₄

= 6.4   x 2/1   = 12.8   moles   of h₂so₄

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

c.

explanation: