Calculate the mass in grams of nacl that is present in 500.0 ml of a 0.900% (m/v) solution.

4.5 grams of NaCl

Explanation:

A concentration of 0.900% (m/V) means that there are 0.9 grams of solute (in this case NaCl, that is, the substance that has been dissolved in another substance, making the solution) in 100 ml of solution. Then, the following proportion applies:

(0.9 grams of NaCl)/(100 ml of solution) = (x grams of NaCl)/(500 ml of solution)  

(0.9/100)*500 = x

4.5 grams of NaCl = x

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

56 moles of   lieter in chemistry