What is the empirical formula of a compound that contains 43.38% sodium, 11.33% carbon, and 45.29% oxygen?

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Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of Na = 43.38 g

Mass of C = 11.33 g

Mass of O = 45.29 g

Step 1 : convert given masses into moles.

Moles of Na=

Moles of C =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Na =

For C =

For O =

The ratio of Na : C: O = 2: 1: 3

Hence the empirical formula is .

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.

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