The reaction of 2-methylbutane with chlorine would yield how many monochloro derivatives (include stereoisomers)?

The reaction of 2 methyl butane with chlorine would yield 5 mono chloro derivatives.

Explanation

The organic compound of 2 methyl butane will have 5 C-H groups.

As butane means 4 CH group and one methyl at 2nd position means one more CH group, so totally 5 CH group is present.

These 5 CH group can react with chlorine and form 5 mono chloro derivatives like CH3Cl, CH2Cl etc.

The chirality present in the anti-bonded carbon atoms leads to the exhibition of stereoisomerism while forming mono chloro derivatives.

Thus, it can be confirmed that 5 mono chloro derivatives will be produced when 2 methyl butane reacts with chlorine.

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a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o