Determine the volume of 0.150 m naoh solution required to neutralize each sample of hydrochloric acid. the neutralization reaction is: naoh(aq) + hcl(aq) → h2o(l) + nacl(aq) 25 ml of a 0.150 m hcl solution 55 ml of a 0.055 m hcl solution 175 ml of a 0.885 m hcl solution

The Volume of NaOH required to neutralize

1) 25 mL of a 0.150M HCl solution is 25 mL

2) 55 mL of a 0.055M HCl solution is 20.2 mL

3) 175 mL of 0.885M HCl solution is 1032.5 mL

Explanation: Neutralization reactions are defined as the reactions when an acid reacts with a base to form a salt and water.

For the reaction of HCl and NaOH,

To calculate the molarity of NaOH, we use the formula:

1.) 25 mL of a 0.150M of HCl solution.

Putting the values in above equation, we get

2.) 55 mL of a 0.055M of HCl solution.

Putting the values in above equation, we get

3.) 175 mL of a 0.885M of HCl solution.

Putting the values in above equation, we get

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >

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