At constant temperature, a sample of helium at 760. torr in a closed container was compressed from 5.00 l to 3.00 l, with no change in moles or temperature. what was the new pressure exerted by the helium on its container? 2280 torr 800. torr 15.0 torr 3800 torr 1270 torr

At constant temperature and moles, the answer can simply becomes P1V1 = P2V2. The original sample is 760 torr and 5.00 l, and was then compressed to 3.00 l. (760 torr)(5.00 l ) = (3.00 l)(X torr), X = 1270 torr. The new pressure exerted by helium on its container is 1270 torr.