In the following reaction, how many grams of nitroglycerin c3h5(no3)3 will decompose to give 120 grams of water? 4c3h5(no3)3(l) 12co2(g) + 6n2(g) + 10h2o(g) + o2(g) the molar mass of nitroglycerin is 227.0995 grams and that of water is 18.0158 grams. 1260.3 grams 3781.67 grams 23.8 grams 3.8 grams 605.07 grams

1) Chemical equation

4C3H5(NO3)3(l) 12CO2(g) + 6N2(g) + 10H2O(g) + O2(g)



2) Molar ratios

4 mol C3H5(NO3)3 : 10 mol H2O

3) Convert grams of water into number of moles:

numer of moles = mass in grams / molar mass = 120 g / 18.0158 g/mol =

number of moles = 6.66 moles H2O.

4) use proportion and solve for x

4 mol C3H5(NO3)3 / 10 mol H2O = x / 6.66 mol H2O

=> x = 6.66 mol H2O * 4 mol C3H5(NO3)3 / 10 mol H2O = 2.66 mol C3H5(NO3)3

5) Convert 2.66 mol C3H5(NO3)3 into grams

mass in grams = molar mass * number of moles = 227.0995 g * 2.66 mol = 605.07 g

605.07 g

The answer should be vaporization