What volume will 6.745g of neon gas occupy at standard temp and pressure?

Explanation:

It is given that mass of neon is 6.745 g and molar mass of neon is 20 g/mol.

Hence, calculate the number of moles as follows.

            No. of moles =

Putting the given values into the above formula as follows.

          No. of moles =

                                =

                                = 0.34 mol

Also, at standard conditions value of temperature is 298 K and pressure is 1 atm.

So, putting the values into ideal gas equation and calculate the value of volume as follows.

                          PV = nRT

                  V = 8.31 L

Thus, we can conclude that volume of given neon gas is 8.31 L.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml