In basic solution, se2− and so32− ions react spontaneously and e o cell = 0.35 v. (a) write the balanced half-reactions for this process. include the states for each reactant and product. (b) if e o sulfite is −0.57 v, calculate e o selenium . 2se2−(aq) + 2so32−(aq) + 3h2o(l) → 2se(s) + 6oh−(aq) + s2o32−(aq)

(a)    Write balanced half-reactions for the process:

Oxidation: Se^2- (aq) → Se (s) + 2e-

Reduction: 2So3^2- (aq) + 3H2O (l) + 4e- → S2O3^2- + 6OH- (aq)

(b)   If E sulfite is 0.57 V, calculate E selenium:

E anode = E cathode – E cell

= -0.57 – 0.35

= -.092

out of these options:

ability to burn paper

pure sodium reacting violently with water

the boiling point of water

helium does not tend to react with anything

i would say this is a physical property:

helium does not tend to react with anything

why? :

i said helium does not tend to react with anything because well, it reacts to ! but ability to burn paper, pure sodium reacting violently with water, & the boiling point of water are chemical or

physical properties: the properties of a substance that can be observed without changing the chemical makeup of the substance

chemical properties: properties of a substance relating to the chemical nature and reactivity of the substance

gas

explanation:

smoke is the matter of a gas