What force is required to keep a 10 mg water droplet moving in this circular arc?

The solution for this problem is:

With a mass of 10 mg or convert this into kilograms by:

We know that 1 mg = 1x10^-6 kilograms, so solving this will give us

10 * 10^ -5 in kilograms.

Then, we compute a force of ma F=ma where m is the mass and acceleration is m/s^2

F = 0.00001 [(2.5m/s^2)/ (0.16 m)] 

= 3.9 * 10 ^ -4 N or F=.0.0004 N 

- decrease the number of plants and animals living in the water.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.