Why does it conduct more before and after this minimum point?

Let me give you an example. Lets say that we have an amount of Ba(OH)2 compared to H2SO4. And let's say that the Ba(OH)2 dissociates as Ba+2 + 2 OH-. H2SO4 dissociates as 2 H+ + SO4-2. So, what happens here is that when the conductivity is at a minimum it means that stoichiometric amounts of Ba(OH)2 and H2SO4 are present and the only materials you can find there in the reaction vessel are H2O and BaSO4. That is why it conduct more before and after this minimum point

Cause its being chemically applied?

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.