Amixture of propane and butane is fed into a furnace where it is mixed with air. the furnace exhaust leaves the furnace at 305°c, 763.0 mmhg and contains only n2, o2, co2, and h2o. the partial pressure of o2 in the exhaust is 100.7 mmhg and the partial pressure of co2 in the exhaust is 33.57 mmhg.

In this item, I supposed, that we are determine the molar fraction of oxygen and carbon dioxide in the sample. This can be done by dividing their respective partial pressures by the total pressure of the sample.

   O2 : mole fraction = (100.7 mmHg) / (763.00 mmHg)  = 0.13

   CO2 : mole fraction = (33.57 mmHg) / (763.00 mmHg) = 0.044

Answers: O2 = 0.13
               CO2 = 0.044