If 15.0 g of a solid dry ice (co2) is placed into an evacuated 5.00 l container and allowed sublime until it is entirely in the gas phase, what pressure (in atm) will the gas exert at 299 k?

Data:

mass, m = 15.0 grams

Molecule = CO2

volume, V = 5.00 liter

temperature, T = 298 K

pressure, P = ?

Formulas:

PV = nRT

n = m / molar mass

Solution:

molar mass of CO2 = 44.01 g/mol

n = 15.0 g / 44.01 g/mol = 0.3408 mol

P = nRT / V = 0.3408 mol * 0.0821 atm*liter/K*mol * 299K / 5.00 liter

P = 1.67 Pa

P = 1.67 Pa