Assuming ideal gas behavior, what is the pressure in atm exerted by 1.57 mol cl2(g) confined to a volume of 1.50 l at 273k?

The formula for ideal gas law is:

P V = n R T

where

P is pressure = ?

V is volume = 1.50 L

n is number of moles = 1.57 mol

R is gas constant = 0.08205746 L atm / mol K

T is temperature = 273 K

P = 1.57 mol * 0.08205746 L atm / mol K * 273 K / 1.50 L

P = 23.45 atm

a is the correct answer