What will be final temperature if you mix the 50.g of water at 0.0oc to 50.g of water at 100.0oc?

Given:

Mass of water = 50 g

Temperature of cold water Tc= 0 C

Temperature of hot water Th= 100 C

To determine:

Final temperature Tf of water

Explanation:

Heat (Q) absorbed or evolved by a substance is given as-

Q = mc(Tf-Ti)

m = mass

c = specific heat

Tf and Ti are the final and initial temperatures

In this case:

Heat lost by hot water = Heat gained by cold water

-mc(Tf - 100 ) = mc(Tf-0)

-Tf + 100 = Tf

2Tf = 100, i.e. Tf = 50 C

Ans: the final temperature is 50 C