Stannous fluoride is formed when a tin cation with charge 4+ combines with a fluorine anion with charge 1-. how will you derive the formula for stannous fluoride?

The formula for stannous fluoride is SnF4.

The tin cation has a charge of 4+ and a fluorine anion has a charge of 1-. Using the crisscross method, we move the charge of the tin cation to the subscript position of the fluorine anion and the charge of the fluorine anion to the subscript position of the tin cation. So, we get Sn1F4. The ratio one-to-four cannot be reduced further. Since the subscript of Sn is 1, we can drop it. So the formula of stannous fluoride becomes SnF4.

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.