Chemistry, 12.07.2019 15:50 photon22

Hydrochloric acid reacts with calcium to form hydrogen and calcium chloride. if 100 grams of hydrochloric acid reacts with 100 grams of calcium, what is the limiting reactant? 2hcl + ca → cacl2 + h2

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Answer from: desiwill01

Answer is hydrochloric acid

Hope this helps!

Answer from: Turtlelover05

- The limiting reactant is HCl.

Explanation: The balanced equation is:

$2HCl+Ca\rightarrow CaCl_2+H_2$

It's a stoichiometry problem. Masses of both the reactants are given and the questions asks to find out the limiting reactant.

We convert the given grams of each reactant to moles on dividing by its molar mass. Now, we can calculate the moles of any of the product on multiplying the moles of the reactant by mole ratio.

We do this starting with both the reactants and see which one gives less number of moles of the product. The limiting reactant is the one giving least number of moles of the product.

Molar mass of HCl is 36.46 gram per mol and that of Ca is 40.08 gram per mol.

Let's say we calculate the moles of hydrogen gas produced in the reaction. Mole ratio of H_2 to HCl is 1:2 and the mole ratio of H_2 to Ca is 1:1 .

The calculations are as shown below:

$100gHCl(\frac{1molHCl}{36.46gHCl})(\frac{1molH_2}{2molHCl})$

= 1.37 mol [tex[H_2[/tex]

$100gCa(\frac{1molCa}{40.08gCa})(\frac{1molH_2}{1molCa})$

= 2.50 mol H_2

From above calculations, we get the least moles of hydrogen gas from 100 grams of HCl. So, the limiting reactant is HCl.

Answer from: Quest

your answers are a,b,,e and f

i hope this

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.