How many chlorine atoms are expected in the products of this chemical reaction? 2sb + 3cl2 ?

We expect 3 chlorine atoms per molecule of product produced.

Explanation:

Given the reactants 2 Sb + 3 Cl2. As you can see in periodic table, Cl always acts with an oxidation state of -1, while Sb can act with +3 or +5.  If reactants are balanced in the given part of the reaction, it means that the product must be 2SbCl3. In this reaction Sb has an oxidation state of +3.

Then 2 Sb + 3Cl2 ⇒ 2 SbCl3, so there are 3 atoms of chlorine per molecule of product produced.

If Sb was acting with +5, you need 5 atoms of chlorine per product and then

2Sb + 5Cl2 ⇒ 2SbCl5, this way you need more atoms than you have.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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