1.what percent of light passes through the sample if its absorbance a=2? 2. for the best calibration curve, the transmittance values (%t) should fall within the range from 10% to 90%. what is the approximate range of corresponding absorbance values? 3. what is the absorbance of the solution if the percent transmittance for it is 10%?

1. The formula for absorbance is given as:

A = log (Io / I)

where A is absorbance, Io is initial intensity, and I is final light intensity

 

log (Io / I) = A

log (Io / I) = 2

Io / I = 100

 

Taking the reverse which is I / Io:

 

I / Io = 1 / 100

I / Io = 0.01

 

Therefore this means that only 0.01 fraction of light or 1% passes through the sample.

 

2. What is meant by transmittance values is actually the value of I / Io. So calculating for A:

 

at 10% transmittance = 0.10

A = log (Io / I)

A = log (1 / 0.10)

A = 1

 

at 90% transmittance = 0.90

A = log (Io / I)

A = log (1 / 0.90)

A = 0.046

 

So the absorbance should be from 0.046 to 1

 

3. at 10% transmittance = 0.10

A = log (Io / I)

A = log (1 / 0.10)

A = 1

The answer is c) pyrite

The answer to the question: choose the correct statement.  a) when ethane reacts with fluorine gas the product is less stable.b) addition reactions of unsaturated hydrocarbons and halogens requires a high activation energy.  c)the double covalent bond within unsaturated hydrocarbons requires a lot of energy to break.  d)the double covalent bond within unsaturated hydrocarbons can be broken easily.is: a) when ethane reacts with fluorine gas the product is less stable.