Asample of an unknown gas effuses in 12.1 min. an equal volume of h2 in the same apparatus under the same conditions effuses in 2.42 min. what is the molar mass of the unknown gas?

MW H2 = 2

MW 2 = ?

rate 1 = 1/12.1

rate 2 = 2.42

aopply graham law

Rate1/rate2 = sqrt(MW2/MW1)

(12.1/2.42)^2 = MW2/2

MW = 2(12.1/2.42)^2 = 50 g/mol

Therefore, the molar mass of the unknown gas is 50 g/mol

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.