How many grams of cuso4 5h20 are needed to prepare a 0.020 m stock solution?

Molar mass of CuSO4*5H2O = 63.5 + 32 + 4(16) + 5(18) = 249.5 g/mole 

molarity is calculated as follows:
molarity = number of moles of solutes/liters of solution

We will assume that the number of liters = 1
Substituting in the above equation:
0.02 = number of moles of CuSO4*5H2O / 1
number of moles = 0.02 moles

number of moles = mass/molar mass
mass = number of moles * molar mass
mass = 0.02 * 249.5 = 4.99 grams

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic