Suppose a small amount of lead(ii) chloride got into your ba(oh)2 sample before your titration, contaminating it. how do you think this contamination would affect your calculated concentration for the sample

Actually this depends on what kind of titration is being done. If we are titrating Ba(OH)2 using an acid, it actually does not matter that some Pb(OH)2 is formed because the acid will still neutralize even those OH- ions that combined with lead Pb.

But other than that, generally we can say that the calculated concentration can be affected because lead (II) chloride would co-precipitate with Ba(OH)2 to form Pb(OH)2

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

answer carbon and three oxygen atoms;