Write the balanced molecular and net ionic equations for the reaction between aluminum metal and silver nitrate. identify the oxidation and reduction half-reactions.

Well in this case, silver nitrate is reduced:

Ag+  +  e−  → Ag(s) ↓

Meanwhile, the aluminum is oxidized forming a positive ion:

Al(s)  →  Al3+  +  3e−

To get the overall reaction,  we add the half equations so that the electrons are eliminated:

Al(s)  +   3Ag+  →  Al3+  +  3Ag(s)

And similarly:

Al(s)  +  3AgNO3(aq)  →  Al(NO3)3(aq)  +  3Ag(s)

the answer would be a

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.