What is the molality of a solution that has 3 mol of glucose in 6 kg of water?

0.5 m

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

where,

n= moles of solute

Moles of glucose = 3 moles

= weight of solvent (water) in g  = 6 kg = 6000 g   (1kg=1000g)

Now put all the given values in the formula of molality, we get

Therefore, the molality of solution will be 0.5 mole/kg.

i believe the answer is 5,000