If you have 6 moles of reactant a and excess of b and c, how much product e would be formed? 3a+5b+1c=> 2d+1e

From the reaction you can state the molar ratios:

3 mol A : 5 mol B : 1 mol C : 2 mol D : 1 mol E.

Given that B and C are in excess, you know that reactant A is the limiting reactant, which means that is reacts completely. So, you can use the number of moles of reactant B to find how many moles of the products are produced.

For that, you build a proportion with the molar ratios between A and E,  and the number of moles of A that reacted:

=> 3 mol A / 1 mol E = 6 mol A / x => x = 6 mol A * 1 mol E / 3 mol A

=> x = 6*1/3 mol E = 2 mol E.

2 moles of E.

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.

Thermohaline circulation and gyres