Complete and balance the molecular equation, including phases, for the reaction of aqueous ammonium bromide, nh4br, and aqueous lead(ii) acetate, pb(c2h3o2)2.omplete and balance the molecular equation, including phases, for the reaction of aqueous ammonium bromide, nh4br, and aqueous lead(ii) acetate, pb(c2h3o2)2.

2NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq)  → PbBr₂(s) + 2NH4C₂H₃O₂(aq)

Explanation:

Unbalanced:

NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq) → PbBr₂(s) + NH₄C₂H₃O₂(aq)

There is two and one acetate ion on the reactant and product side respectively. Similarly there are one and two bromine atoms on the reactant and product side respectively.

Balanced:

2NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq)  → PbBr₂(s) + 2NH₄C₂H₃O₂(aq)

To balance the bromine and acetate ions on both side of the reaction we place a 2 coefficient before NH₄Br and NH₄C₂H₃O.

i think the answer is terrae but not 100 percent sure. ▓▬▬ §

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).