Calculate the energy(j) change associated with an electron transition from n=2 to n=5 in a bohr hydrogen atom. put answer in scientific notation.

4.58*10^(-19) J

Explanation:

Using the Rydberg's equation:

where

is  the wavelength of the photon;

R is the Rydberg's constant = 1.0974*10^7 m^(-1)

final level is 5 and initial level is 2.

Energy change is calculated with the next formula:

E = h*c/λ

where h is the Planck's constant = 6.626*10^(-34) J*s, and c is the speed of light = 299,792,458 m/s

E = 6.626*10^(-34)*299,792,458/-4.339*10^(-7)

E = 4.58*10^(-19) J