Hello, do these calculations using table 1 look correct? Thank you Table 1.
Sugar (Sucrose) Data
Mass of unchewed gum 3.7(g)
Mass of chewed gum 2.0 (g)
Mass of sugar 1.7(g)
Percent sugar
46%

Post-Lab Questions
1.What is the percent sugar? Show your calculations.
mass of sugar (1.7) ÷ mass of unchewed gum ( 3.7) × 100 = 45.94 (46%)
2.What is the molar mass of sugar (sucrose, C12H22O11)? Show your calculations.
C=12×12=144
H=1×22=22
O=16×11=176
To get the molar mass of the entire compound you, 144 + 22 + 176 = 342 g/mol
3.Convert the mass of dissolved sugar to moles. Show your calculations.
1.7 g ÷ 342 g/mol = 0.00497 moles
4.Convert the moles of sugar to molecules of sugar. Show your calculations.
0.00497 mole × 6.022 × 10^23 = 2.992934 × 10^21 molecules
5.Imagine that you used four pieces of gum instead of two. Calculate the number of moles. Show your calculations.
In theory, assuming the sticks of gum were exactly the same mass and sugar content, the moles would double.
2 ÷ 342 g/mol × 1.7 = 0.00994 moles
6.How does the mass of the saliva alter the experimental data?
It is impossible to blot off all the saliva with a paper towel because the gum sticks to the paper, so it adds more mass to the chewed gum and therefore alters the amount and percent of sugar calculations.