The procedure calls for 2.00 mL of the liquid reactant, 2,4-pentanedione, to be used in the reaction. It has a density of 0.975 g/mL. How many grams of this reactant will be used in the reaction

Just took the quiz on edgenuity and the correct answer is "c.  4.54 x  10–12  j"

Is there any options, for this

Ibelieve it’s 1.95m

  the volume of  0.220 m k2s    solution  required  to  completely  react with 175 ml  of 0.115m co(no3)2  calculate the moles  of co(no3)2 =  molarity x volume/1000175 x0.115/1000= 0.02  moleswrite  the reacting  equationk2s(aq)  +  co(no3)2  = 2 kno3(aq)  + cos(s)by  use  of mole ratio between k2s to co(no3)2 which  is  1: 1 the moles of k2s is therefore = 175  x0.115/1000= 0.02  molesvolume = moles/molarity=0.02/0.22=0.09  ml  of k2s