The reaction 2N2O5(g) --> O2(g) +4NO2(g) is first order in N2O5. For this reaction at 45ºC, the rate constant k = 1.0 × 10–5 s–1. For a particular experiment ([N2O5]0 = 1.0 × 10–3 M), calculate [N2O5] after 2.6 × 105 seconds. a. 7.4 x 10^-5 M b. 1.0 x 10^-3 M c. 2.6 M d. 9.5 M

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

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