Using Boyle’s Law, calculate the new volume of the weather balloon at a higher altitude. Assume the volume of the balloon at ground level is 10.0 m3 where the atmospheric pressure is 1.00 atm. What will be its new volume at an altitude of 15 km where the atmospheric pressure is 0.350 atm?

Explanation:

V1 = 10 m^3

P1 = 1.00 atmospheres

V2 = ?

P2 = 0.35

Formula

V1 * P1 = V2 * P2

Solution

10 * 1 = x * 0.35           Combine the left and divide both sides by 0.35

10/0.35 = x

x = 28.57 m^3

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.