490g of Na2SO4 are dissolved in 80g of water. Determine the molality of this solution

43.13mol/kg

Explanation:

since molality is the concentration of a solution in moles of solute per kilogram of solvent.

moles of Na2SO4 = mass/molar mass

= 490/142

= 3.45 mol

mass of water in kg= 80/1000

=0.08kg

molality is therefore= 3.45/0.08

=43.5mol/kg

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.