Molybdenum can form a wide series of halide compounds, including four different fluoride compounds. The percent by mass of molybdenum in the four compounds is 63. 0%, 56. 0%, 50. 0%, and 46. 0%. Determine the formula and name for each of the four different molybdenum fluorides.

1. Formula of compound => MoF₃
Name of compound => Molybdenum trifluoride
2. Formula of compound => MoF₄
Name of compound => Molybdenum tetrafluoride
3. Formula of compound => MoF₅
Name of compound => Molybdenum pentafluoride
4. Formula of compound => MoF₆
Name of compound => Molybdenum hexafluoride
1. Determination of the name and formula of the molybdenum fluoride having 63.0% of molybdenum.
Molybdenum (Mo) = 63.0%
Fluorine (F) = 100 – 63 = 37%
Formula =?
Mo = 63.0%
F = 37%
Divide by their molar mass
Mo = 63.0 / 96 = 0.656
F = 37 / 19 = 1.947
Divide by the smallest
Mo = 0.656 / 0.656 = 1
F = 1.947 / 0.656 = 3
Therefore,
Formula of compound => MoF₃
Name of compound => Molybdenum trifluoride
2. Determination of the name and formula of the molybdenum fluoride having 56.0% of molybdenum.
Molybdenum (Mo) = 56.0%,
Fluorine (F) = 100 – 56 = 44%
Formula =?
Mo = 56%
F = 44%
Divide by their molar mass
Mo = 56 / 96 = 0.583
F = 44 / 19 = 2.316
Divide by the smallest
Mo = 0.583 / 0.583 = 1
F = 2.316 / 0.583 = 4
Therefore,
Formula of compound => MoF₄
Name of compound => Molybdenum tetrafluoride
3. Determination of the name and formula of the molybdenum fluoride having 50.0% of molybdenum.
Molybdenum (Mo) = 50.0%,
Fluorine (F) = 100 – 50 = 50%
Formula =?
Mo = 50%
F = 50%
Divide by their molar mass
Mo = 50 / 96 = 0.520
F = 50 / 19 = 2.632
Divide by the smallest
Mo = 0.520 / 0.520 = 1
F = 2.632 / 0.520 = 5
Therefore,
Formula of compound => MoF₅
Name of compound => Molybdenum pentafluoride
4. Determination of the name and formula of the molybdenum fluoride having 46.0% of molybdenum.
Molybdenum (Mo) = 46.0%,
Fluorine (F) = 100 – 46 = 54%
Formula =?
Mo = 46%
F = 54%
Divide by their molar mass
Mo = 46 / 96 = 0.479
F = 54 / 19 = 2.842
Divide by the smallest
Mo = 0.479 / 0.479 = 1
F = 2.842 / 0.479 = 6
Therefore,
Formula of compound => MoF₆
Name of compound => Molybdenum hexafluoride

Deposition is the transition of matter going from gas to solid without passing through the liquid phase.a.) gas—-> solid