Calculate the freezing point of a solution of 3.46gram of compound, X, in 160gram of benzene. When separate sample of X was vaporized, it's density was found to be 3.27g/Lat116degee Celsius and 773torr. freezing point of pure benzene is 5.45degree Celsius, and constant freezing is 5.12degree Celsius kg/mol.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

the answer is 0.8m.

by: nicholas